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5111321437 is a prime number
BaseRepresentation
bin1001100001010100…
…01001001101011101
3111012012212000212101
410300222021031131
540431444241222
62203105205101
7240443341525
oct46052111535
914165760771
105111321437
1121932314a2
12ba7930791
13635c37571
14366b9c685
151edae5927
hex130a8935d

5111321437 has 2 divisors, whose sum is σ = 5111321438. Its totient is φ = 5111321436.

The previous prime is 5111321417. The next prime is 5111321459. The reversal of 5111321437 is 7341231115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3915130041 + 1196191396 = 62571^2 + 34586^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5111321437 is a prime.

It is a super-2 number, since 2×51113214372 = 52251213664671489938, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5111321407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555660718 + 2555660719.

It is an arithmetic number, because the mean of its divisors is an integer number (2555660719).

Almost surely, 25111321437 is an apocalyptic number.

It is an amenable number.

5111321437 is a deficient number, since it is larger than the sum of its proper divisors (1).

5111321437 is an equidigital number, since it uses as much as digits as its factorization.

5111321437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2520, while the sum is 28.

The square root of 5111321437 is about 71493.5062575616. The cubic root of 5111321437 is about 1722.5733785164.

The spelling of 5111321437 in words is "five billion, one hundred eleven million, three hundred twenty-one thousand, four hundred thirty-seven".