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5111341 is a prime number
BaseRepresentation
bin10011011111111000101101
3100121200102221
4103133320231
52302030331
6301315341
761305604
oct23377055
910550387
105111341
112981254
121865b51
13109c681
14970a3b
156ae711
hex4dfe2d

5111341 has 2 divisors, whose sum is σ = 5111342. Its totient is φ = 5111340.

The previous prime is 5111317. The next prime is 5111377. The reversal of 5111341 is 1431115.

5111341 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5062500 + 48841 = 2250^2 + 221^2 .

It is a cyclic number.

It is not a de Polignac number, because 5111341 - 213 = 5103149 is a prime.

It is a super-2 number, since 2×51113412 = 52251613636562, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5111641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555670 + 2555671.

It is an arithmetic number, because the mean of its divisors is an integer number (2555671).

Almost surely, 25111341 is an apocalyptic number.

It is an amenable number.

5111341 is a deficient number, since it is larger than the sum of its proper divisors (1).

5111341 is an equidigital number, since it uses as much as digits as its factorization.

5111341 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 60, while the sum is 16.

The square root of 5111341 is about 2260.8275033713. The cubic root of 5111341 is about 172.2575576165.

Adding to 5111341 its reverse (1431115), we get a palindrome (6542456).

The spelling of 5111341 in words is "five million, one hundred eleven thousand, three hundred forty-one".