Base | Representation |
---|---|
bin | 101111100110100110… |
… | …101111000100110111 |
3 | 11212221012011120212011 |
4 | 233212212233010313 |
5 | 1314140032213411 |
6 | 35251540505051 |
7 | 3456433020355 |
oct | 574646570467 |
9 | 155835146764 |
10 | 51113554231 |
11 | 1a74a2a5903 |
12 | 9aa59ab187 |
13 | 4a87687c5c |
14 | 268c59a7d5 |
15 | 14e2506c21 |
hex | be69af137 |
51113554231 has 2 divisors, whose sum is σ = 51113554232. Its totient is φ = 51113554230.
The previous prime is 51113554213. The next prime is 51113554241. The reversal of 51113554231 is 13245531115.
Together with previous prime (51113554213) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51113554231 - 217 = 51113423159 is a prime.
It is a super-2 number, since 2×511135542312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51113554193 and 51113554202.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51113554241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25556777115 + 25556777116.
It is an arithmetic number, because the mean of its divisors is an integer number (25556777116).
Almost surely, 251113554231 is an apocalyptic number.
51113554231 is a deficient number, since it is larger than the sum of its proper divisors (1).
51113554231 is an equidigital number, since it uses as much as digits as its factorization.
51113554231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9000, while the sum is 31.
The spelling of 51113554231 in words is "fifty-one billion, one hundred thirteen million, five hundred fifty-four thousand, two hundred thirty-one".
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