5111401133533 has 2 divisors, whose sum is σ = 5111401133534. Its totient is φ = 5111401133532.

The previous prime is 5111401133477. The next prime is 5111401133537. The reversal of 5111401133533 is 3353311041115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5108856637284 + 2544496249 = 2260278^2 + 50443^2 .

It is a cyclic number.

It is not a de Polignac number, because 5111401133533 - 2³³ = 5102811198941 is a prime.

It is a super-2 number, since 2×5111401133533² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5111401133495 and 5111401133504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5111401133537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555700566766 + 2555700566767.

It is an arithmetic number, because the mean of its divisors is an integer number (2555700566767).

Almost surely, 2^{5111401133533} is an apocalyptic number.

It is an amenable number.

5111401133533 is a deficient number, since it is larger than the sum of its proper divisors (1).

5111401133533 is an equidigital number, since it uses as much as digits as its factorization.

5111401133533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8100, while the sum is 31.

Adding to 5111401133533 its reverse (3353311041115), we get a palindrome (8464712174648).

The spelling of 5111401133533 in words is "five trillion, one hundred eleven billion, four hundred one million, one hundred thirty-three thousand, five hundred thirty-three".