Base | Representation |
---|---|
bin | 101111100110101000… |
… | …110101110110101011 |
3 | 11212221020012122010112 |
4 | 233212220311312223 |
5 | 1314140202400113 |
6 | 35252000404535 |
7 | 3456440510012 |
oct | 574650656653 |
9 | 155836178115 |
10 | 51114106283 |
11 | 1a74a642649 |
12 | 9aa601674b |
13 | 4a8781c306 |
14 | 268c6a1a79 |
15 | 14e25b55a8 |
hex | be6a35dab |
51114106283 has 2 divisors, whose sum is σ = 51114106284. Its totient is φ = 51114106282.
The previous prime is 51114106273. The next prime is 51114106343. The reversal of 51114106283 is 38260141115.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51114106283 is a prime.
It is a super-2 number, since 2×511141062832 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51114106213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25557053141 + 25557053142.
It is an arithmetic number, because the mean of its divisors is an integer number (25557053142).
Almost surely, 251114106283 is an apocalyptic number.
51114106283 is a deficient number, since it is larger than the sum of its proper divisors (1).
51114106283 is an equidigital number, since it uses as much as digits as its factorization.
51114106283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 32.
Adding to 51114106283 its reverse (38260141115), we get a palindrome (89374247398).
The spelling of 51114106283 in words is "fifty-one billion, one hundred fourteen million, one hundred six thousand, two hundred eighty-three".
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