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51115030 = 257171993
BaseRepresentation
bin1100001011111…
…1010000010110
310120011220122021
43002333100112
5101041140110
65023323354
71160320261
oct302772026
9116156567
1051115030
112694252a
121515055a
13a788aa5
146b07cd8
15474a2da
hex30bf416

51115030 has 16 divisors (see below), whose sum is σ = 93304224. Its totient is φ = 20157760.

The previous prime is 51114983. The next prime is 51115049. The reversal of 51115030 is 3051115.

51115030 = 3802 + 3812 + ... + 5922.

51115030 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×511150302 = 5225492583801800, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 51114995 and 51115013.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35287 + ... + 36706.

It is an arithmetic number, because the mean of its divisors is an integer number (5831514).

Almost surely, 251115030 is an apocalyptic number.

51115030 is a deficient number, since it is larger than the sum of its proper divisors (42189194).

51115030 is a wasteful number, since it uses less digits than its factorization.

51115030 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72071.

The product of its (nonzero) digits is 75, while the sum is 16.

The square root of 51115030 is about 7149.4776032938. The cubic root of 51115030 is about 371.1215784701.

Adding to 51115030 its reverse (3051115), we get a palindrome (54166145).

The spelling of 51115030 in words is "fifty-one million, one hundred fifteen thousand, thirty".

Divisors: 1 2 5 10 71 142 355 710 71993 143986 359965 719930 5111503 10223006 25557515 51115030