Base | Representation |
---|---|
bin | 101111100110101110… |
… | …010100101100000100 |
3 | 11212221022220122100101 |
4 | 233212232110230010 |
5 | 1314141034341200 |
6 | 35252051253444 |
7 | 3456455643403 |
oct | 574656245404 |
9 | 155838818311 |
10 | 51115543300 |
11 | 1a750434268 |
12 | 9aa65aa284 |
13 | 4a87c03413 |
14 | 268c95763a |
15 | 14e279b26a |
hex | be6b94b04 |
51115543300 has 18 divisors (see below), whose sum is σ = 110920729178. Its totient is φ = 20446217280.
The previous prime is 51115543291. The next prime is 51115543331. The reversal of 51115543300 is 334551115.
51115543300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 3 ways, for example, as 105513984 + 51010029316 = 10272^2 + 225854^2 .
It is a super-2 number, since 2×511155433002 (a number of 22 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 255577617 + ... + 255577816.
Almost surely, 251115543300 is an apocalyptic number.
51115543300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
51115543300 is an abundant number, since it is smaller than the sum of its proper divisors (59805185878).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51115543300 is a wasteful number, since it uses less digits than its factorization.
51115543300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 511155447 (or 511155440 counting only the distinct ones).
The product of its (nonzero) digits is 4500, while the sum is 28.
It can be divided in two parts, 511155 and 43300, that added together give a palindrome (554455).
The spelling of 51115543300 in words is "fifty-one billion, one hundred fifteen million, five hundred forty-three thousand, three hundred".
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