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511200103411 is a prime number
BaseRepresentation
bin1110111000001011110…
…01101000101111110011
31210212111102011220202101
413130011321220233303
531333414211302121
61030501520201231
751635005120144
oct7340571505763
91725442156671
10511200103411
11187887149a08
12830a7a69217
133928a6677ba
141aa56901acb
15d46e04c491
hex7705e68bf3

511200103411 has 2 divisors, whose sum is σ = 511200103412. Its totient is φ = 511200103410.

The previous prime is 511200103409. The next prime is 511200103433. The reversal of 511200103411 is 114301002115.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 511200103411 - 21 = 511200103409 is a prime.

It is a super-2 number, since 2×5112001034112 (a number of 24 digits) contains 22 as substring.

Together with 511200103409, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (511200103441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255600051705 + 255600051706.

It is an arithmetic number, because the mean of its divisors is an integer number (255600051706).

Almost surely, 2511200103411 is an apocalyptic number.

511200103411 is a deficient number, since it is larger than the sum of its proper divisors (1).

511200103411 is an equidigital number, since it uses as much as digits as its factorization.

511200103411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 511200103411 its reverse (114301002115), we get a palindrome (625501105526).

The spelling of 511200103411 in words is "five hundred eleven billion, two hundred million, one hundred three thousand, four hundred eleven".