Base | Representation |
---|---|
bin | 10111001111110010110010… |
… | …11100101111100110110111 |
3 | 20201000001011201211202010010 |
4 | 23213321121130233212313 |
5 | 23200023133033323442 |
6 | 300420144002231303 |
7 | 13524212150645646 |
oct | 1347713134574667 |
9 | 221001151752103 |
10 | 51120201464247 |
11 | 15319a57031183 |
12 | 5897530055533 |
13 | 226a7ca853796 |
14 | c8a333a3b35d |
15 | 5d9b48dc4b9c |
hex | 2e7e5972f9b7 |
51120201464247 has 32 divisors (see below), whose sum is σ = 69585211152576. Its totient is φ = 33370245708800.
The previous prime is 51120201464209. The next prime is 51120201464323. The reversal of 51120201464247 is 74246410202115.
It is a cyclic number.
It is not a de Polignac number, because 51120201464247 - 27 = 51120201464119 is a prime.
It is a super-2 number, since 2×511202014642472 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51120201464047) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1986549193 + ... + 1986574925.
It is an arithmetic number, because the mean of its divisors is an integer number (2174537848518).
Almost surely, 251120201464247 is an apocalyptic number.
51120201464247 is a deficient number, since it is larger than the sum of its proper divisors (18465009688329).
51120201464247 is a wasteful number, since it uses less digits than its factorization.
51120201464247 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50291.
The product of its (nonzero) digits is 107520, while the sum is 39.
The spelling of 51120201464247 in words is "fifty-one trillion, one hundred twenty billion, two hundred one million, four hundred sixty-four thousand, two hundred forty-seven".
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