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51121117 is a prime number
BaseRepresentation
bin1100001100000…
…0101111011101
310120012012222201
43003000233131
5101041333432
65023411501
71160344105
oct303005735
9116165881
1051121117
1126947063
1215153b91
13a78b7a8
146b0a205
15474bee7
hex30c0bdd

51121117 has 2 divisors, whose sum is σ = 51121118. Its totient is φ = 51121116.

The previous prime is 51121073. The next prime is 51121121. The reversal of 51121117 is 71112115.

51121117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39363076 + 11758041 = 6274^2 + 3429^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51121117 is a prime.

It is a super-2 number, since 2×511211172 = 5226737206655378, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 51121094 and 51121103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51121127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25560558 + 25560559.

It is an arithmetic number, because the mean of its divisors is an integer number (25560559).

Almost surely, 251121117 is an apocalyptic number.

It is an amenable number.

51121117 is a deficient number, since it is larger than the sum of its proper divisors (1).

51121117 is an equidigital number, since it uses as much as digits as its factorization.

51121117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 70, while the sum is 19.

The square root of 51121117 is about 7149.9032860592. The cubic root of 51121117 is about 371.1363094757.

The spelling of 51121117 in words is "fifty-one million, one hundred twenty-one thousand, one hundred seventeen".