511212340097 has 2 divisors, whose sum is σ = 511212340098. Its totient is φ = 511212340096.

The previous prime is 511212340073. The next prime is 511212340099. The reversal of 511212340097 is 790043212115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 430210057216 + 81002282881 = 655904^2 + 284609^2 .

It is a cyclic number.

It is not a de Polignac number, because 511212340097 - 2¹⁰ = 511212339073 is a prime.

It is a super-2 number, since 2×511212340097² (a number of 24 digits) contains 22 as substring.

Together with 511212340099, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (511212340099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255606170048 + 255606170049.

It is an arithmetic number, because the mean of its divisors is an integer number (255606170049).

Almost surely, 2^511212340097 is an apocalyptic number.

It is an amenable number.

511212340097 is a deficient number, since it is larger than the sum of its proper divisors (1).

511212340097 is an equidigital number, since it uses as much as digits as its factorization.

511212340097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 35.

The spelling of 511212340097 in words is "five hundred eleven billion, two hundred twelve million, three hundred forty thousand, ninety-seven".