Search a number
-
+
5112132015504 = 243106502750323
BaseRepresentation
bin100101001100100001011…
…0100000001010110010000
3200002201022021021201020110
41022121002310001112100
51132224121243444004
614512251522441320
71035224253111213
oct112310264012620
920081267251213
105112132015504
1116a1052282458
126a6922803240
132b10c21ab4b7
141395ddb8b77a
158cea1aa7589
hex4a642d01590

5112132015504 has 20 divisors (see below), whose sum is σ = 13206341040176. Its totient is φ = 1704044005152.

The previous prime is 5112132015493. The next prime is 5112132015509. The reversal of 5112132015504 is 4055102312115.

It is a super-2 number, since 2×51121320155042 (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (5112132015509) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53251375114 + ... + 53251375209.

Almost surely, 25112132015504 is an apocalyptic number.

It is an amenable number.

5112132015504 is an abundant number, since it is smaller than the sum of its proper divisors (8094209024672).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

5112132015504 is a wasteful number, since it uses less digits than its factorization.

5112132015504 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 106502750334 (or 106502750328 counting only the distinct ones).

The product of its (nonzero) digits is 6000, while the sum is 30.

Adding to 5112132015504 its reverse (4055102312115), we get a palindrome (9167234327619).

The spelling of 5112132015504 in words is "five trillion, one hundred twelve billion, one hundred thirty-two million, fifteen thousand, five hundred four".

Divisors: 1 2 3 4 6 8 12 16 24 48 106502750323 213005500646 319508250969 426011001292 639016501938 852022002584 1278033003876 1704044005168 2556066007752 5112132015504