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5112136242641 is a prime number
BaseRepresentation
bin100101001100100001100…
…0100001001010111010001
3200002201022120020110210002
41022121003010021113101
51132224123334231031
614512252153215345
71035224334045221
oct112310304112721
920081276213702
105112136242641
1116a10546aa35a
126a6924101555
132b10c302b56c
1413960056c081
158cea213eccb
hex4a6431095d1

5112136242641 has 2 divisors, whose sum is σ = 5112136242642. Its totient is φ = 5112136242640.

The previous prime is 5112136242637. The next prime is 5112136242671. The reversal of 5112136242641 is 1462426312115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3419004393025 + 1693131849616 = 1849055^2 + 1301204^2 .

It is a cyclic number.

It is not a de Polignac number, because 5112136242641 - 22 = 5112136242637 is a prime.

It is a super-2 number, since 2×51121362426412 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5112136242595 and 5112136242604.

It is not a weakly prime, because it can be changed into another prime (5112136242601) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556068121320 + 2556068121321.

It is an arithmetic number, because the mean of its divisors is an integer number (2556068121321).

Almost surely, 25112136242641 is an apocalyptic number.

It is an amenable number.

5112136242641 is a deficient number, since it is larger than the sum of its proper divisors (1).

5112136242641 is an equidigital number, since it uses as much as digits as its factorization.

5112136242641 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 69120, while the sum is 38.

The spelling of 5112136242641 in words is "five trillion, one hundred twelve billion, one hundred thirty-six million, two hundred forty-two thousand, six hundred forty-one".