Base | Representation |
---|---|
bin | 100101001100100001100… |
… | …0100001001010111100110 |
3 | 200002201022120020110210212 |
4 | 1022121003010021113212 |
5 | 1132224123334231122 |
6 | 14512252153215422 |
7 | 1035224334045251 |
oct | 112310304112746 |
9 | 20081276213725 |
10 | 5112136242662 |
11 | 16a10546aa379 |
12 | 6a6924101572 |
13 | 2b10c302b587 |
14 | 13960056c098 |
15 | 8cea213ece2 |
hex | 4a6431095e6 |
5112136242662 has 4 divisors (see below), whose sum is σ = 7668204363996. Its totient is φ = 2556068121330.
The previous prime is 5112136242641. The next prime is 5112136242671. The reversal of 5112136242662 is 2662426312115.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×51121362426623 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1278034060664 + ... + 1278034060667.
It is an arithmetic number, because the mean of its divisors is an integer number (1917051090999).
Almost surely, 25112136242662 is an apocalyptic number.
5112136242662 is a deficient number, since it is larger than the sum of its proper divisors (2556068121334).
5112136242662 is a wasteful number, since it uses less digits than its factorization.
5112136242662 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2556068121333.
The product of its digits is 207360, while the sum is 41.
The spelling of 5112136242662 in words is "five trillion, one hundred twelve billion, one hundred thirty-six million, two hundred forty-two thousand, six hundred sixty-two".
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