Search a number
-
+
5112144201431 is a prime number
BaseRepresentation
bin100101001100100001110…
…0010100000011011010111
3200002201100010012211012002
41022121003202200123113
51132224132403421211
614512253035545515
71035224461513541
oct112310342403327
920081303184162
105112144201431
1116a1059145973
126a69268bb29b
132b10c4886cc7
14139601640691
158cea2bb303b
hex4a6438a06d7

5112144201431 has 2 divisors, whose sum is σ = 5112144201432. Its totient is φ = 5112144201430.

The previous prime is 5112144201419. The next prime is 5112144201449. The reversal of 5112144201431 is 1341024412115.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5112144201431 - 222 = 5112140007127 is a prime.

It is a super-2 number, since 2×51121442014312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5112144201394 and 5112144201403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5112144291431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556072100715 + 2556072100716.

It is an arithmetic number, because the mean of its divisors is an integer number (2556072100716).

Almost surely, 25112144201431 is an apocalyptic number.

5112144201431 is a deficient number, since it is larger than the sum of its proper divisors (1).

5112144201431 is an equidigital number, since it uses as much as digits as its factorization.

5112144201431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 29.

Adding to 5112144201431 its reverse (1341024412115), we get a palindrome (6453168613546).

The spelling of 5112144201431 in words is "five trillion, one hundred twelve billion, one hundred forty-four million, two hundred one thousand, four hundred thirty-one".