511216450403 has 2 divisors, whose sum is σ = 511216450404. Its totient is φ = 511216450402.

The previous prime is 511216450399. The next prime is 511216450447. The reversal of 511216450403 is 304054612115.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 511216450403 - 2² = 511216450399 is a prime.

It is a super-2 number, since 2×511216450403² (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 511216450403.

It is not a weakly prime, because it can be changed into another prime (511216450483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255608225201 + 255608225202.

It is an arithmetic number, because the mean of its divisors is an integer number (255608225202).

Almost surely, 2^511216450403 is an apocalyptic number.

511216450403 is a deficient number, since it is larger than the sum of its proper divisors (1).

511216450403 is an equidigital number, since it uses as much as digits as its factorization.

511216450403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 32.

The spelling of 511216450403 in words is "five hundred eleven billion, two hundred sixteen million, four hundred fifty thousand, four hundred three".