Base | Representation |
---|---|
bin | 100101001100100011110… |
… | …0001100001011001010111 |
3 | 200002201111210000012002111 |
4 | 1022121013201201121113 |
5 | 1132224302012131434 |
6 | 14512303424451451 |
7 | 1035226232652523 |
oct | 112310741413127 |
9 | 20081453005074 |
10 | 5112211052119 |
11 | 16a1092955876 |
12 | 6a6945179b87 |
13 | 2b1105692222 |
14 | 13960a482d83 |
15 | 8cea89ba964 |
hex | 4a647861657 |
5112211052119 has 2 divisors, whose sum is σ = 5112211052120. Its totient is φ = 5112211052118.
The previous prime is 5112211052087. The next prime is 5112211052147. The reversal of 5112211052119 is 9112501122115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5112211052119 - 25 = 5112211052087 is a prime.
It is a super-2 number, since 2×51122110521192 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5112211052159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556105526059 + 2556105526060.
It is an arithmetic number, because the mean of its divisors is an integer number (2556105526060).
Almost surely, 25112211052119 is an apocalyptic number.
5112211052119 is a deficient number, since it is larger than the sum of its proper divisors (1).
5112211052119 is an equidigital number, since it uses as much as digits as its factorization.
5112211052119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 31.
The spelling of 5112211052119 in words is "five trillion, one hundred twelve billion, two hundred eleven million, fifty-two thousand, one hundred nineteen".
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