Base | Representation |
---|---|
bin | 100101001100100011110… |
… | …0010011110111100101010 |
3 | 200002201111210110222221002 |
4 | 1022121013202132330222 |
5 | 1132224302043213414 |
6 | 14512303434115002 |
7 | 1035226235052536 |
oct | 112310742367452 |
9 | 20081453428832 |
10 | 5112211304234 |
11 | 16a1093008231 |
12 | 6a694527ba62 |
13 | 2b110574cbc8 |
14 | 13960a50abc6 |
15 | 8cea8a1a4de |
hex | 4a64789ef2a |
5112211304234 has 16 divisors (see below), whose sum is σ = 7752778592328. Its totient is φ = 2527988554752.
The previous prime is 5112211304197. The next prime is 5112211304251. The reversal of 5112211304234 is 4324031122115.
It is a happy number.
It can be written as a sum of positive squares in 4 ways, for example, as 5036725390225 + 75485914009 = 2244265^2 + 274747^2 .
It is a super-2 number, since 2×51122113042342 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5112211304197 and 5112211304206.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8916557 + ... + 9472560.
Almost surely, 25112211304234 is an apocalyptic number.
5112211304234 is a deficient number, since it is larger than the sum of its proper divisors (2640567288094).
5112211304234 is a wasteful number, since it uses less digits than its factorization.
5112211304234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18390649.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 5112211304234 its reverse (4324031122115), we get a palindrome (9436242426349).
The spelling of 5112211304234 in words is "five trillion, one hundred twelve billion, two hundred eleven million, three hundred four thousand, two hundred thirty-four".
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