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5112348737 is a prime number
BaseRepresentation
bin1001100001011100…
…00100000001000001
3111012021210020001112
410300232010001001
540432230124422
62203143213105
7240455150546
oct46056040101
914167706045
105112348737
112193873301
12ba8147195
13636207032
14366d88bcd
151edc49ee2
hex130b84041

5112348737 has 2 divisors, whose sum is σ = 5112348738. Its totient is φ = 5112348736.

The previous prime is 5112348707. The next prime is 5112348739. The reversal of 5112348737 is 7378432115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4271406736 + 840942001 = 65356^2 + 28999^2 .

It is a cyclic number.

It is not a de Polignac number, because 5112348737 - 28 = 5112348481 is a prime.

It is a super-2 number, since 2×51123487372 = 52272219217410990338, which contains 22 as substring.

Together with 5112348739, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 5112348694 and 5112348703.

It is not a weakly prime, because it can be changed into another prime (5112348739) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556174368 + 2556174369.

It is an arithmetic number, because the mean of its divisors is an integer number (2556174369).

Almost surely, 25112348737 is an apocalyptic number.

It is an amenable number.

5112348737 is a deficient number, since it is larger than the sum of its proper divisors (1).

5112348737 is an equidigital number, since it uses as much as digits as its factorization.

5112348737 is an evil number, because the sum of its binary digits is even.

The product of its digits is 141120, while the sum is 41.

The square root of 5112348737 is about 71500.6904651976. The cubic root of 5112348737 is about 1722.6887747085.

The spelling of 5112348737 in words is "five billion, one hundred twelve million, three hundred forty-eight thousand, seven hundred thirty-seven".