Base | Representation |
---|---|
bin | 10111001111111011010100… |
… | …00000110110111100010111 |
3 | 20201000110222102111121110002 |
4 | 23213331222000312330113 |
5 | 23200112014212143411 |
6 | 300422221434521515 |
7 | 13524433365465263 |
oct | 1347755200667427 |
9 | 221013872447402 |
10 | 51124774334231 |
11 | 15320993323074 |
12 | 58983a759629b |
13 | 226b079062200 |
14 | c8a6490b50a3 |
15 | 5d9d155a933b |
hex | 2e7f6a036f17 |
51124774334231 has 24 divisors (see below), whose sum is σ = 56134084398336. Its totient is φ = 46534366887840.
The previous prime is 51124774334111. The next prime is 51124774334267. The reversal of 51124774334231 is 13243347742115.
It is not a de Polignac number, because 51124774334231 - 218 = 51124774072087 is a prime.
It is a super-2 number, since 2×511247743342312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51124774334531) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3851666 + ... + 10820576.
It is an arithmetic number, because the mean of its divisors is an integer number (2338920183264).
Almost surely, 251124774334231 is an apocalyptic number.
51124774334231 is a deficient number, since it is larger than the sum of its proper divisors (5009310064105).
51124774334231 is a wasteful number, since it uses less digits than its factorization.
51124774334231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6969543 (or 6969530 counting only the distinct ones).
The product of its digits is 1693440, while the sum is 47.
The spelling of 51124774334231 in words is "fifty-one trillion, one hundred twenty-four billion, seven hundred seventy-four million, three hundred thirty-four thousand, two hundred thirty-one".
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