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5113055176807 is a prime number
BaseRepresentation
bin100101001100111100111…
…0101100110100001100111
3200002210200121101011110211
41022121321311212201213
51132233014111124212
614512523301200251
71035256162623454
oct112317165464147
920083617334424
105113055176807
1116a1486394186
126a6b3ba00087
132b120b5241a6
1413968a61682b
158d007b5b9a7
hex4a679d66867

5113055176807 has 2 divisors, whose sum is σ = 5113055176808. Its totient is φ = 5113055176806.

The previous prime is 5113055176709. The next prime is 5113055176871. The reversal of 5113055176807 is 7086715503115.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5113055176807 is a prime.

It is a super-2 number, since 2×51130551768072 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5113055170807) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556527588403 + 2556527588404.

It is an arithmetic number, because the mean of its divisors is an integer number (2556527588404).

Almost surely, 25113055176807 is an apocalyptic number.

5113055176807 is a deficient number, since it is larger than the sum of its proper divisors (1).

5113055176807 is an equidigital number, since it uses as much as digits as its factorization.

5113055176807 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 882000, while the sum is 49.

The spelling of 5113055176807 in words is "five trillion, one hundred thirteen billion, fifty-five million, one hundred seventy-six thousand, eight hundred seven".