Base | Representation |
---|---|
bin | 100101001100111111010… |
… | …0011001011010110111001 |
3 | 200002210220010010122012121 |
4 | 1022121332203023112321 |
5 | 1132233144330424032 |
6 | 14512535203441241 |
7 | 1035261142606156 |
oct | 112317643132671 |
9 | 20083803118177 |
10 | 5113134233017 |
11 | 16a1516a80298 |
12 | 6a6b62386221 |
13 | 2b1221a13b05 |
14 | 139696d1522d |
15 | 8d00ea75a97 |
hex | 4a67e8cb5b9 |
5113134233017 has 2 divisors, whose sum is σ = 5113134233018. Its totient is φ = 5113134233016.
The previous prime is 5113134232993. The next prime is 5113134233021. The reversal of 5113134233017 is 7103324313115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2931779515536 + 2181354717481 = 1712244^2 + 1476941^2 .
It is a cyclic number.
It is not a de Polignac number, because 5113134233017 - 27 = 5113134232889 is a prime.
It is a super-2 number, since 2×51131342330172 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5113134236017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556567116508 + 2556567116509.
It is an arithmetic number, because the mean of its divisors is an integer number (2556567116509).
Almost surely, 25113134233017 is an apocalyptic number.
It is an amenable number.
5113134233017 is a deficient number, since it is larger than the sum of its proper divisors (1).
5113134233017 is an equidigital number, since it uses as much as digits as its factorization.
5113134233017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22680, while the sum is 34.
The spelling of 5113134233017 in words is "five trillion, one hundred thirteen billion, one hundred thirty-four million, two hundred thirty-three thousand, seventeen".
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