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51131537603 is a prime number
BaseRepresentation
bin101111100111101011…
…010101100011000011
311212222110000020101222
4233213223111203003
51314204133200403
635253422145255
73460041620126
oct574753254303
9155873006358
1051131537603
111a759468aa3
129aaba2222b
134a8b3134c3
142690b1c3bd
1514e3daa338
hexbe7ad58c3

51131537603 has 2 divisors, whose sum is σ = 51131537604. Its totient is φ = 51131537602.

The previous prime is 51131537563. The next prime is 51131537663. The reversal of 51131537603 is 30673513115.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 51131537603 - 214 = 51131521219 is a prime.

It is a super-4 number, since 4×511315376034 (a number of 44 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (51131537663) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25565768801 + 25565768802.

It is an arithmetic number, because the mean of its divisors is an integer number (25565768802).

Almost surely, 251131537603 is an apocalyptic number.

51131537603 is a deficient number, since it is larger than the sum of its proper divisors (1).

51131537603 is an equidigital number, since it uses as much as digits as its factorization.

51131537603 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28350, while the sum is 35.

The spelling of 51131537603 in words is "fifty-one billion, one hundred thirty-one million, five hundred thirty-seven thousand, six hundred three".