Base | Representation |
---|---|
bin | 101111100111101011… |
… | …010101100011111111 |
3 | 11212222110000020111012 |
4 | 233213223111203333 |
5 | 1314204133201123 |
6 | 35253422145435 |
7 | 3460041620243 |
oct | 574753254377 |
9 | 155873006435 |
10 | 51131537663 |
11 | 1a759469048 |
12 | 9aaba2227b |
13 | 4a8b31353b |
14 | 2690b1c423 |
15 | 14e3daa378 |
hex | be7ad58ff |
51131537663 has 2 divisors, whose sum is σ = 51131537664. Its totient is φ = 51131537662.
The previous prime is 51131537603. The next prime is 51131537683. The reversal of 51131537663 is 36673513115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51131537663 - 226 = 51064428799 is a prime.
It is a super-2 number, since 2×511315376632 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 51131537663.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51131537603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25565768831 + 25565768832.
It is an arithmetic number, because the mean of its divisors is an integer number (25565768832).
Almost surely, 251131537663 is an apocalyptic number.
51131537663 is a deficient number, since it is larger than the sum of its proper divisors (1).
51131537663 is an equidigital number, since it uses as much as digits as its factorization.
51131537663 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 170100, while the sum is 41.
The spelling of 51131537663 in words is "fifty-one billion, one hundred thirty-one million, five hundred thirty-seven thousand, six hundred sixty-three".
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