Base | Representation |
---|---|
bin | 100101001101000001100… |
… | …1000011100011110001111 |
3 | 200002211002110210110101211 |
4 | 1022122003020130132033 |
5 | 1132233324021030221 |
6 | 14512550551315251 |
7 | 1035263065221142 |
oct | 112320310343617 |
9 | 20084073713354 |
10 | 5113211111311 |
11 | 16a155640a076 |
12 | 6a6b8407bb27 |
13 | 2b1234920324 |
14 | 1396a3208059 |
15 | 8d0166ae6e1 |
hex | 4a68321c78f |
5113211111311 has 2 divisors, whose sum is σ = 5113211111312. Its totient is φ = 5113211111310.
The previous prime is 5113211111293. The next prime is 5113211111479. The reversal of 5113211111311 is 1131111123115.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5113211111311 is a prime.
It is a super-2 number, since 2×51132111113112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5113211112311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556605555655 + 2556605555656.
It is an arithmetic number, because the mean of its divisors is an integer number (2556605555656).
Almost surely, 25113211111311 is an apocalyptic number.
5113211111311 is a deficient number, since it is larger than the sum of its proper divisors (1).
5113211111311 is an equidigital number, since it uses as much as digits as its factorization.
5113211111311 is an evil number, because the sum of its binary digits is even.
The product of its digits is 90, while the sum is 22.
Adding to 5113211111311 its reverse (1131111123115), we get a palindrome (6244322234426).
The spelling of 5113211111311 in words is "five trillion, one hundred thirteen billion, two hundred eleven million, one hundred eleven thousand, three hundred eleven".
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