Base | Representation |
---|---|
bin | 100101001101000001110… |
… | …1010011111001101110111 |
3 | 200002211010002120212000101 |
4 | 1022122003222133031313 |
5 | 1132233333312113242 |
6 | 14512551510454531 |
7 | 1035263234120056 |
oct | 112320352371567 |
9 | 20084102525011 |
10 | 5113220035447 |
11 | 16a1560454997 |
12 | 6a6b87064447 |
13 | 2b1236726294 |
14 | 1396a448c39d |
15 | 8d0173739b7 |
hex | 4a683a9f377 |
5113220035447 has 2 divisors, whose sum is σ = 5113220035448. Its totient is φ = 5113220035446.
The previous prime is 5113220035433. The next prime is 5113220035463. The reversal of 5113220035447 is 7445300223115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5113220035447 - 215 = 5113220002679 is a prime.
It is a super-2 number, since 2×51132200354472 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5113220035747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556610017723 + 2556610017724.
It is an arithmetic number, because the mean of its divisors is an integer number (2556610017724).
Almost surely, 25113220035447 is an apocalyptic number.
5113220035447 is a deficient number, since it is larger than the sum of its proper divisors (1).
5113220035447 is an equidigital number, since it uses as much as digits as its factorization.
5113220035447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100800, while the sum is 37.
The spelling of 5113220035447 in words is "five trillion, one hundred thirteen billion, two hundred twenty million, thirty-five thousand, four hundred forty-seven".
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