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511328212793 is a prime number
BaseRepresentation
bin1110111000011011000…
…10010101011100111001
31210212211100020112210022
413130031202111130321
531334200010302133
61030522334100225
751641122044656
oct7341542253471
91725740215708
10511328212793
1118794249a432
128312294a675
13392ab070878
141aa6992cc2d
15d47a405998
hex770d895739

511328212793 has 2 divisors, whose sum is σ = 511328212794. Its totient is φ = 511328212792.

The previous prime is 511328212739. The next prime is 511328212847. The reversal of 511328212793 is 397212823115.

Together with previous prime (511328212739) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (511328212739) and next prime (511328212847).

It can be written as a sum of positive squares in only one way, i.e., 467140809529 + 44187403264 = 683477^2 + 210208^2 .

It is a cyclic number.

It is not a de Polignac number, because 511328212793 - 210 = 511328211769 is a prime.

It is a super-2 number, since 2×5113282127932 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (511328212393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255664106396 + 255664106397.

It is an arithmetic number, because the mean of its divisors is an integer number (255664106397).

Almost surely, 2511328212793 is an apocalyptic number.

It is an amenable number.

511328212793 is a deficient number, since it is larger than the sum of its proper divisors (1).

511328212793 is an equidigital number, since it uses as much as digits as its factorization.

511328212793 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 181440, while the sum is 44.

The spelling of 511328212793 in words is "five hundred eleven billion, three hundred twenty-eight million, two hundred twelve thousand, seven hundred ninety-three".