Base | Representation |
---|---|
bin | 100101001101000100111… |
… | …1011011111001101100011 |
3 | 200002211101102101111011111 |
4 | 1022122021323133031203 |
5 | 1132234042214431141 |
6 | 14513010143524151 |
7 | 1035265651454422 |
oct | 112321173371543 |
9 | 20084342344144 |
10 | 5113325155171 |
11 | 16a16048229a2 |
12 | 6a6bb62b9657 |
13 | 2b12524401bc |
14 | 1396b44132b9 |
15 | 8d0216da381 |
hex | 4a689edf363 |
5113325155171 has 2 divisors, whose sum is σ = 5113325155172. Its totient is φ = 5113325155170.
The previous prime is 5113325155163. The next prime is 5113325155177. The reversal of 5113325155171 is 1715515233115.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5113325155171 - 23 = 5113325155163 is a prime.
It is a super-2 number, since 2×51133251551712 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5113325155177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556662577585 + 2556662577586.
It is an arithmetic number, because the mean of its divisors is an integer number (2556662577586).
Almost surely, 25113325155171 is an apocalyptic number.
5113325155171 is a deficient number, since it is larger than the sum of its proper divisors (1).
5113325155171 is an equidigital number, since it uses as much as digits as its factorization.
5113325155171 is an evil number, because the sum of its binary digits is even.
The product of its digits is 78750, while the sum is 40.
The spelling of 5113325155171 in words is "five trillion, one hundred thirteen billion, three hundred twenty-five million, one hundred fifty-five thousand, one hundred seventy-one".
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