Base | Representation |
---|---|
bin | 10111010000001100101101… |
… | …01001100001000011111010 |
3 | 20201001101002021002022110221 |
4 | 23220012112221201003322 |
5 | 23200240130424441402 |
6 | 300430404241330254 |
7 | 13525213664055334 |
oct | 1350062651410372 |
9 | 221041067068427 |
10 | 51134113124602 |
11 | 15324945882542 |
12 | 589a17303698a |
13 | 226bc06a72381 |
14 | c8ac934ba454 |
15 | 5da1b03a8337 |
hex | 2e8196a610fa |
51134113124602 has 8 divisors (see below), whose sum is σ = 76817559931200. Its totient is φ = 25528259814204.
The previous prime is 51134113124587. The next prime is 51134113124683. The reversal of 51134113124602 is 20642131143115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×511341131246023 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19398372402 + ... + 19398375037.
It is an arithmetic number, because the mean of its divisors is an integer number (9602194991400).
Almost surely, 251134113124602 is an apocalyptic number.
51134113124602 is a deficient number, since it is larger than the sum of its proper divisors (25683446806598).
51134113124602 is a wasteful number, since it uses less digits than its factorization.
51134113124602 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 38796748100.
The product of its (nonzero) digits is 17280, while the sum is 34.
Adding to 51134113124602 its reverse (20642131143115), we get a palindrome (71776244267717).
The spelling of 51134113124602 in words is "fifty-one trillion, one hundred thirty-four billion, one hundred thirteen million, one hundred twenty-four thousand, six hundred two".
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