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5113411999 is a prime number
BaseRepresentation
bin1001100001100100…
…00111100110011111
3111012100210020120121
410300302013212133
540433013140444
62203222055411
7240500166463
oct46062074637
914170706517
105113411999
11219442a133
12ba857a567
136364b9c97
143671844a3
151eddaa084
hex130c8799f

5113411999 has 2 divisors, whose sum is σ = 5113412000. Its totient is φ = 5113411998.

The previous prime is 5113411991. The next prime is 5113412027. The reversal of 5113411999 is 9991143115.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5113411999 - 23 = 5113411991 is a prime.

It is a super-2 number, since 2×51134119992 = 52293964543034352002, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5113411991) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556705999 + 2556706000.

It is an arithmetic number, because the mean of its divisors is an integer number (2556706000).

Almost surely, 25113411999 is an apocalyptic number.

5113411999 is a deficient number, since it is larger than the sum of its proper divisors (1).

5113411999 is an equidigital number, since it uses as much as digits as its factorization.

5113411999 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 43740, while the sum is 43.

The square root of 5113411999 is about 71508.1254054391. The cubic root of 5113411999 is about 1722.8081942185.

The spelling of 5113411999 in words is "five billion, one hundred thirteen million, four hundred eleven thousand, nine hundred ninety-nine".