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5113412477 is a prime number
BaseRepresentation
bin1001100001100100…
…00111101101111101
3111012100210021020022
410300302013231331
540433013144402
62203222101525
7240500201045
oct46062075575
914170707208
105113412477
11219442a528
12ba857a8a5
136364ba274
14367184725
151eddaa2a2
hex130c87b7d

5113412477 has 2 divisors, whose sum is σ = 5113412478. Its totient is φ = 5113412476.

The previous prime is 5113412471. The next prime is 5113412489. The reversal of 5113412477 is 7742143115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4406171641 + 707240836 = 66379^2 + 26594^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5113412477 is a prime.

It is a super-2 number, since 2×51134124772 = 52293974319878551058, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5113412471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556706238 + 2556706239.

It is an arithmetic number, because the mean of its divisors is an integer number (2556706239).

Almost surely, 25113412477 is an apocalyptic number.

It is an amenable number.

5113412477 is a deficient number, since it is larger than the sum of its proper divisors (1).

5113412477 is an equidigital number, since it uses as much as digits as its factorization.

5113412477 is an evil number, because the sum of its binary digits is even.

The product of its digits is 23520, while the sum is 35.

The square root of 5113412477 is about 71508.1287477165. The cubic root of 5113412477 is about 1722.8082479010.

The spelling of 5113412477 in words is "five billion, one hundred thirteen million, four hundred twelve thousand, four hundred seventy-seven".