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511344040351 = 19471314371097
BaseRepresentation
bin1110111000011100111…
…10101101100110011111
31210212212110000200010011
413130032132231212133
531334213033242401
61030524101224051
751641403425314
oct7341636554637
91725773020104
10511344040351
1118795041a961
1283128102027
13392b1422aa1
141aa6ba8cd0b
15d47b9d0451
hex770e7ad99f

511344040351 has 16 divisors (see below), whose sum is σ = 553905538560. Its totient is φ = 470504773440.

The previous prime is 511344040261. The next prime is 511344040373. The reversal of 511344040351 is 153040443115.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-511344040351 is a prime.

It is a super-2 number, since 2×5113440403512 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (511344046351) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2068566 + ... + 2302531.

It is an arithmetic number, because the mean of its divisors is an integer number (34619096160).

Almost surely, 2511344040351 is an apocalyptic number.

511344040351 is a deficient number, since it is larger than the sum of its proper divisors (42561498209).

511344040351 is a wasteful number, since it uses less digits than its factorization.

511344040351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4371294.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 511344040351 its reverse (153040443115), we get a palindrome (664384483466).

The spelling of 511344040351 in words is "five hundred eleven billion, three hundred forty-four million, forty thousand, three hundred fifty-one".

Divisors: 1 19 47 131 893 2489 6157 116983 4371097 83050843 205441559 572613707 3903389621 10879660433 26912844229 511344040351