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5114003 is a prime number
BaseRepresentation
bin10011100000100010010011
3100121211002112
4103200202103
52302122003
6301335535
761316426
oct23404223
910554075
105114003
112983254
1218675ab
1310a094b
149719bd
156b03d8
hex4e0893

5114003 has 2 divisors, whose sum is σ = 5114004. Its totient is φ = 5114002.

The previous prime is 5113993. The next prime is 5114047. The reversal of 5114003 is 3004115.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5114003 - 26 = 5113939 is a prime.

It is an Ulam number.

It is not a weakly prime, because it can be changed into another prime (5114503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557001 + 2557002.

It is an arithmetic number, because the mean of its divisors is an integer number (2557002).

Almost surely, 25114003 is an apocalyptic number.

5114003 is a deficient number, since it is larger than the sum of its proper divisors (1).

5114003 is an equidigital number, since it uses as much as digits as its factorization.

5114003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 14.

The square root of 5114003 is about 2261.4161492304. The cubic root of 5114003 is about 172.2874564915.

Adding to 5114003 its reverse (3004115), we get a palindrome (8118118).

The spelling of 5114003 in words is "five million, one hundred fourteen thousand, three".