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5114503 is a prime number
BaseRepresentation
bin10011100000101010000111
3100121211210001
4103200222013
52302131003
6301342131
761321042
oct23405207
910554701
105114503
112983669
121867947
1310a0c44
14971c59
156b061d
hex4e0a87

5114503 has 2 divisors, whose sum is σ = 5114504. Its totient is φ = 5114502.

The previous prime is 5114491. The next prime is 5114507. The reversal of 5114503 is 3054115.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5114503 - 25 = 5114471 is a prime.

5114503 is a lucky number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5114507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557251 + 2557252.

It is an arithmetic number, because the mean of its divisors is an integer number (2557252).

Almost surely, 25114503 is an apocalyptic number.

5114503 is a deficient number, since it is larger than the sum of its proper divisors (1).

5114503 is an equidigital number, since it uses as much as digits as its factorization.

5114503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 300, while the sum is 19.

The square root of 5114503 is about 2261.5266967250. The cubic root of 5114503 is about 172.2930712008.

Adding to 5114503 its reverse (3054115), we get a palindrome (8168618).

The spelling of 5114503 in words is "five million, one hundred fourteen thousand, five hundred three".