Base | Representation |
---|---|
bin | 10111010000010111110111… |
… | …00100101101101000110011 |
3 | 20201001221112120221202001212 |
4 | 23220023323210231220303 |
5 | 23200334411420102012 |
6 | 300433234353350335 |
7 | 13525515246015446 |
oct | 1350137344555063 |
9 | 221057476852055 |
10 | 51140101331507 |
11 | 15327438a88a71 |
12 | 589b3645683ab |
13 | 226c64c56c376 |
14 | c8b2a08d965d |
15 | 5da410e61b22 |
hex | 2e82fb92da33 |
51140101331507 has 2 divisors, whose sum is σ = 51140101331508. Its totient is φ = 51140101331506.
The previous prime is 51140101331497. The next prime is 51140101331563. The reversal of 51140101331507 is 70513310104115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51140101331507 - 26 = 51140101331443 is a prime.
It is not a weakly prime, because it can be changed into another prime (51140101391507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25570050665753 + 25570050665754.
It is an arithmetic number, because the mean of its divisors is an integer number (25570050665754).
Almost surely, 251140101331507 is an apocalyptic number.
51140101331507 is a deficient number, since it is larger than the sum of its proper divisors (1).
51140101331507 is an equidigital number, since it uses as much as digits as its factorization.
51140101331507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6300, while the sum is 32.
The spelling of 51140101331507 in words is "fifty-one trillion, one hundred forty billion, one hundred one million, three hundred thirty-one thousand, five hundred seven".
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