Base | Representation |
---|---|
bin | 101111101000010011… |
… | …101011010011010111 |
3 | 11220000011220111101202 |
4 | 233220103223103113 |
5 | 1314214340044341 |
6 | 35254440543115 |
7 | 3460230532502 |
oct | 575023532327 |
9 | 156004814352 |
10 | 51142112471 |
11 | 1a76443105a |
12 | 9ab3481a9b |
13 | 4a90576918 |
14 | 26922b2139 |
15 | 14e4c9879b |
hex | be84eb4d7 |
51142112471 has 2 divisors, whose sum is σ = 51142112472. Its totient is φ = 51142112470.
The previous prime is 51142112447. The next prime is 51142112531. The reversal of 51142112471 is 17421124115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51142112471 - 230 = 50068370647 is a prime.
It is a super-3 number, since 3×511421124713 (a number of 33 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51142112771) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25571056235 + 25571056236.
It is an arithmetic number, because the mean of its divisors is an integer number (25571056236).
Almost surely, 251142112471 is an apocalyptic number.
51142112471 is a deficient number, since it is larger than the sum of its proper divisors (1).
51142112471 is an equidigital number, since it uses as much as digits as its factorization.
51142112471 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2240, while the sum is 29.
Adding to 51142112471 its reverse (17421124115), we get a palindrome (68563236586).
The spelling of 51142112471 in words is "fifty-one billion, one hundred forty-two million, one hundred twelve thousand, four hundred seventy-one".
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