51145141312333 has 2 divisors, whose sum is σ = 51145141312334. Its totient is φ = 51145141312332.

The previous prime is 51145141312289. The next prime is 51145141312357. The reversal of 51145141312333 is 33321314154115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 48420750084004 + 2724391228329 = 6958502^2 + 1650573^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-51145141312333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 51145141312292 and 51145141312301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51145141342333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25572570656166 + 25572570656167.

It is an arithmetic number, because the mean of its divisors is an integer number (25572570656167).

Almost surely, 2^{51145141312333} is an apocalyptic number.

It is an amenable number.

51145141312333 is a deficient number, since it is larger than the sum of its proper divisors (1).

51145141312333 is an equidigital number, since it uses as much as digits as its factorization.

51145141312333 is an evil number, because the sum of its binary digits is even.

The product of its digits is 64800, while the sum is 37.

Adding to 51145141312333 its reverse (33321314154115), we get a palindrome (84466455466448).

The spelling of 51145141312333 in words is "fifty-one trillion, one hundred forty-five billion, one hundred forty-one million, three hundred twelve thousand, three hundred thirty-three".