Base | Representation |
---|---|
bin | 10111010000101101000101… |
… | …11111111100110111100011 |
3 | 20201010000221222221022222212 |
4 | 23220112202333330313203 |
5 | 23201031233022421233 |
6 | 300442401430552335 |
7 | 13526400600555425 |
oct | 1350264277746743 |
9 | 221100858838885 |
10 | 51151500201443 |
11 | 1533125838a734 |
12 | 58a1605b086ab |
13 | 2270748000b15 |
14 | c8ba62758815 |
15 | 5da87ba3ea48 |
hex | 2e85a2ffcde3 |
51151500201443 has 2 divisors, whose sum is σ = 51151500201444. Its totient is φ = 51151500201442.
The previous prime is 51151500201409. The next prime is 51151500201463. The reversal of 51151500201443 is 34410200515115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51151500201443 - 214 = 51151500185059 is a prime.
It is not a weakly prime, because it can be changed into another prime (51151500201463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25575750100721 + 25575750100722.
It is an arithmetic number, because the mean of its divisors is an integer number (25575750100722).
Almost surely, 251151500201443 is an apocalyptic number.
51151500201443 is a deficient number, since it is larger than the sum of its proper divisors (1).
51151500201443 is an equidigital number, since it uses as much as digits as its factorization.
51151500201443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 51151500201443 its reverse (34410200515115), we get a palindrome (85561700716558).
The spelling of 51151500201443 in words is "fifty-one trillion, one hundred fifty-one billion, five hundred million, two hundred one thousand, four hundred forty-three".
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