Base | Representation |
---|---|
bin | 10111010000110000001001… |
… | …10100010011011100000010 |
3 | 20201010012012100222120000200 |
4 | 23220120010310103130002 |
5 | 23201043113134042310 |
6 | 300443232333430030 |
7 | 13526456346033135 |
oct | 1350300464233402 |
9 | 221105170876020 |
10 | 51153141315330 |
11 | 15331a1a7928aa |
12 | 58a19a363b316 |
13 | 227094a000422 |
14 | c8bb7a6b221c |
15 | 5da925b609c0 |
hex | 2e8604d13702 |
51153141315330 has 48 divisors (see below), whose sum is σ = 133017396762744. Its totient is φ = 13638865443840.
The previous prime is 51153141315299. The next prime is 51153141315349. The reversal of 51153141315330 is 3351314135115.
51153141315330 is a `hidden beast` number, since 5 + 1 + 1 + 5 + 3 + 1 + 4 + 1 + 315 + 330 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 32638631798529 + 18514509516801 = 5713023^2 + 4302849^2 .
It is a super-2 number, since 2×511531413153302 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 40462351 + ... + 41707410.
Almost surely, 251153141315330 is an apocalyptic number.
51153141315330 is an abundant number, since it is smaller than the sum of its proper divisors (81864255447414).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51153141315330 is a wasteful number, since it uses less digits than its factorization.
51153141315330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82176691 (or 82176688 counting only the distinct ones).
The product of its (nonzero) digits is 40500, while the sum is 36.
The spelling of 51153141315330 in words is "fifty-one trillion, one hundred fifty-three billion, one hundred forty-one million, three hundred fifteen thousand, three hundred thirty".
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