Base | Representation |
---|---|
bin | 10111010000110010000100… |
… | …10001010000001000100111 |
3 | 20201010021212012222201112012 |
4 | 23220121002101100020213 |
5 | 23201102221103023101 |
6 | 300443522523344435 |
7 | 13526524035262454 |
oct | 1350310221201047 |
9 | 221107765881465 |
10 | 51154172314151 |
11 | 153323a9759545 |
12 | 58a203098211b |
13 | 2270a827a20ba |
14 | c8bc375ac82b |
15 | 5da986416bbb |
hex | 2e8642450227 |
51154172314151 has 2 divisors, whose sum is σ = 51154172314152. Its totient is φ = 51154172314150.
The previous prime is 51154172314061. The next prime is 51154172314171. The reversal of 51154172314151 is 15141327145115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51154172314151 - 218 = 51154172052007 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 51154172314099 and 51154172314108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51154172314171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25577086157075 + 25577086157076.
It is an arithmetic number, because the mean of its divisors is an integer number (25577086157076).
Almost surely, 251154172314151 is an apocalyptic number.
51154172314151 is a deficient number, since it is larger than the sum of its proper divisors (1).
51154172314151 is an equidigital number, since it uses as much as digits as its factorization.
51154172314151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 84000, while the sum is 41.
Adding to 51154172314151 its reverse (15141327145115), we get a palindrome (66295499459266).
The spelling of 51154172314151 in words is "fifty-one trillion, one hundred fifty-four billion, one hundred seventy-two million, three hundred fourteen thousand, one hundred fifty-one".
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