Base | Representation |
---|---|
bin | 100101001110000110110… |
… | …0010001011110010011001 |
3 | 200010001002022001102222201 |
4 | 1022130031202023302121 |
5 | 1132303102434131041 |
6 | 14514013220050201 |
7 | 1035404452013614 |
oct | 112341542136231 |
9 | 20101068042881 |
10 | 5115533114521 |
11 | 16a2538099495 |
12 | 6a7511833961 |
13 | 2b15149ca61b |
14 | 13984376317b |
15 | 8d10047a631 |
hex | 4a70d88bc99 |
5115533114521 has 2 divisors, whose sum is σ = 5115533114522. Its totient is φ = 5115533114520.
The previous prime is 5115533114519. The next prime is 5115533114537. The reversal of 5115533114521 is 1254113355115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3670055916121 + 1445477198400 = 1915739^2 + 1202280^2 .
It is a cyclic number.
It is not a de Polignac number, because 5115533114521 - 21 = 5115533114519 is a prime.
Together with 5115533114519, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (5115533114501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557766557260 + 2557766557261.
It is an arithmetic number, because the mean of its divisors is an integer number (2557766557261).
Almost surely, 25115533114521 is an apocalyptic number.
It is an amenable number.
5115533114521 is a deficient number, since it is larger than the sum of its proper divisors (1).
5115533114521 is an equidigital number, since it uses as much as digits as its factorization.
5115533114521 is an evil number, because the sum of its binary digits is even.
The product of its digits is 45000, while the sum is 37.
Adding to 5115533114521 its reverse (1254113355115), we get a palindrome (6369646469636).
The spelling of 5115533114521 in words is "five trillion, one hundred fifteen billion, five hundred thirty-three million, one hundred fourteen thousand, five hundred twenty-one".
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