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51156351444013 is a prime number
BaseRepresentation
bin10111010000110110001000…
…01001111110010000101101
320201010111111002101222201121
423220123010021332100231
523201121201432202023
6300444523045540541
713526632035466654
oct1350330411762055
9221114432358647
1051156351444013
1115333317824012
1258a253a714751
13227103c0a725a
14c8bda2b7619b
155daa628aed5d
hex2e86c427e42d

51156351444013 has 2 divisors, whose sum is σ = 51156351444014. Its totient is φ = 51156351444012.

The previous prime is 51156351443963. The next prime is 51156351444041. The reversal of 51156351444013 is 31044415365115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44535909231529 + 6620442212484 = 6673523^2 + 2573022^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51156351444013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51156351484013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25578175722006 + 25578175722007.

It is an arithmetic number, because the mean of its divisors is an integer number (25578175722007).

Almost surely, 251156351444013 is an apocalyptic number.

It is an amenable number.

51156351444013 is a deficient number, since it is larger than the sum of its proper divisors (1).

51156351444013 is an equidigital number, since it uses as much as digits as its factorization.

51156351444013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432000, while the sum is 43.

The spelling of 51156351444013 in words is "fifty-one trillion, one hundred fifty-six billion, three hundred fifty-one million, four hundred forty-four thousand, thirteen".