Base | Representation |
---|---|
bin | 100101001110001010011… |
… | …1001111010011000011101 |
3 | 200010001101220202001112202 |
4 | 1022130110321322120131 |
5 | 1132303331113301242 |
6 | 14514033354341245 |
7 | 1035410513062433 |
oct | 112342471723035 |
9 | 20101356661482 |
10 | 5115656775197 |
11 | 16a25a09805a1 |
12 | 6a754712a825 |
13 | 2b1534506817 |
14 | 139855d52d53 |
15 | 8d10b255932 |
hex | 4a714e7a61d |
5115656775197 has 2 divisors, whose sum is σ = 5115656775198. Its totient is φ = 5115656775196.
The previous prime is 5115656775169. The next prime is 5115656775233. The reversal of 5115656775197 is 7915776565115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4404579466681 + 711077308516 = 2098709^2 + 843254^2 .
It is a cyclic number.
It is not a de Polignac number, because 5115656775197 - 28 = 5115656774941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5115656775157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557828387598 + 2557828387599.
It is an arithmetic number, because the mean of its divisors is an integer number (2557828387599).
Almost surely, 25115656775197 is an apocalyptic number.
It is an amenable number.
5115656775197 is a deficient number, since it is larger than the sum of its proper divisors (1).
5115656775197 is an equidigital number, since it uses as much as digits as its factorization.
5115656775197 is an evil number, because the sum of its binary digits is even.
The product of its digits is 69457500, while the sum is 65.
The spelling of 5115656775197 in words is "five trillion, one hundred fifteen billion, six hundred fifty-six million, seven hundred seventy-five thousand, one hundred ninety-seven".
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