Base | Representation |
---|---|
bin | 10111010001000100000001… |
… | …01001000010011011101111 |
3 | 20201011012201210111101200011 |
4 | 23220202000221002123233 |
5 | 23201231440004441341 |
6 | 300452155040114051 |
7 | 13530314606046616 |
oct | 1350420051023357 |
9 | 221135653441604 |
10 | 51163808671471 |
11 | 153364a4180411 |
12 | 58a3a80005927 |
13 | 227195a03a792 |
14 | c8c4ad31287d |
15 | 5dad4c3e3b81 |
hex | 2e8880a426ef |
51163808671471 has 2 divisors, whose sum is σ = 51163808671472. Its totient is φ = 51163808671470.
The previous prime is 51163808671433. The next prime is 51163808671483. The reversal of 51163808671471 is 17417680836115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51163808671471 - 235 = 51129448933103 is a prime.
It is a super-3 number, since 3×511638086714713 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51163808674471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25581904335735 + 25581904335736.
It is an arithmetic number, because the mean of its divisors is an integer number (25581904335736).
Almost surely, 251163808671471 is an apocalyptic number.
51163808671471 is a deficient number, since it is larger than the sum of its proper divisors (1).
51163808671471 is an equidigital number, since it uses as much as digits as its factorization.
51163808671471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6773760, while the sum is 58.
The spelling of 51163808671471 in words is "fifty-one trillion, one hundred sixty-three billion, eight hundred eight million, six hundred seventy-one thousand, four hundred seventy-one".
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