Base | Representation |
---|---|
bin | 1100001100101… |
… | …1111110011011 |
3 | 10120021120002221 |
4 | 3003023332123 |
5 | 101044322011 |
6 | 5024404511 |
7 | 1160625211 |
oct | 303137633 |
9 | 116246087 |
10 | 51167131 |
11 | 26978694 |
12 | 15176737 |
13 | a7a6712 |
14 | 6b1ccb1 |
15 | 475a971 |
hex | 30cbf9b |
51167131 has 2 divisors, whose sum is σ = 51167132. Its totient is φ = 51167130.
The previous prime is 51167117. The next prime is 51167141. The reversal of 51167131 is 13176115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51167131 - 211 = 51165083 is a prime.
It is a super-2 number, since 2×511671312 = 5236150589542322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51167096 and 51167105.
It is not a weakly prime, because it can be changed into another prime (51167141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25583565 + 25583566.
It is an arithmetic number, because the mean of its divisors is an integer number (25583566).
Almost surely, 251167131 is an apocalyptic number.
51167131 is a deficient number, since it is larger than the sum of its proper divisors (1).
51167131 is an equidigital number, since it uses as much as digits as its factorization.
51167131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 630, while the sum is 25.
The square root of 51167131 is about 7153.1203680632. The cubic root of 51167131 is about 371.2476290628.
The spelling of 51167131 in words is "fifty-one million, one hundred sixty-seven thousand, one hundred thirty-one".
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