Base | Representation |
---|---|
bin | 100101001110101011110… |
… | …1101101000101111011001 |
3 | 200010011022000211102012211 |
4 | 1022131113231220233121 |
5 | 1132313130033140211 |
6 | 14514340514235121 |
7 | 1035450343146613 |
oct | 112352755505731 |
9 | 20104260742184 |
10 | 5116777630681 |
11 | 16a301663a942 |
12 | 6a77ba585aa1 |
13 | 2b16827aa112 |
14 | 139920b5ddb3 |
15 | 8d17485ae21 |
hex | 4a757b68bd9 |
5116777630681 has 2 divisors, whose sum is σ = 5116777630682. Its totient is φ = 5116777630680.
The previous prime is 5116777630669. The next prime is 5116777630733. The reversal of 5116777630681 is 1860367776115.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3180101824656 + 1936675806025 = 1783284^2 + 1391645^2 .
It is a cyclic number.
It is not a de Polignac number, because 5116777630681 - 215 = 5116777597913 is a prime.
It is a super-3 number, since 3×51167776306813 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (5116777630631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2558388815340 + 2558388815341.
It is an arithmetic number, because the mean of its divisors is an integer number (2558388815341).
Almost surely, 25116777630681 is an apocalyptic number.
It is an amenable number.
5116777630681 is a deficient number, since it is larger than the sum of its proper divisors (1).
5116777630681 is an equidigital number, since it uses as much as digits as its factorization.
5116777630681 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8890560, while the sum is 58.
The spelling of 5116777630681 in words is "five trillion, one hundred sixteen billion, seven hundred seventy-seven million, six hundred thirty thousand, six hundred eighty-one".
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