Base | Representation |
---|---|
bin | 100101001110110100011… |
… | …1111001100110000101111 |
3 | 200010012001020011121221021 |
4 | 1022131220333030300233 |
5 | 1132314223231303333 |
6 | 14514425350115011 |
7 | 1035460462434265 |
oct | 112355077146057 |
9 | 20105036147837 |
10 | 5117067447343 |
11 | 16a3155199445 |
12 | 6a787b64ba67 |
13 | 2b16ca850a77 |
14 | 13994b442435 |
15 | 8d19000782d |
hex | 4a768fccc2f |
5117067447343 has 2 divisors, whose sum is σ = 5117067447344. Its totient is φ = 5117067447342.
The previous prime is 5117067447227. The next prime is 5117067447353. The reversal of 5117067447343 is 3437447607115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5117067447343 - 217 = 5117067316271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5117067447353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2558533723671 + 2558533723672.
It is an arithmetic number, because the mean of its divisors is an integer number (2558533723672).
Almost surely, 25117067447343 is an apocalyptic number.
5117067447343 is a deficient number, since it is larger than the sum of its proper divisors (1).
5117067447343 is an equidigital number, since it uses as much as digits as its factorization.
5117067447343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5927040, while the sum is 52.
The spelling of 5117067447343 in words is "five trillion, one hundred seventeen billion, sixty-seven million, four hundred forty-seven thousand, three hundred forty-three".
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