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5117067447673 is a prime number
BaseRepresentation
bin100101001110110100011…
…1111001100110101111001
3200010012001020011122101111
41022131220333030311321
51132314223231311143
614514425350120321
71035460462435246
oct112355077146571
920105036148344
105117067447673
1116a3155199715
126a787b6500a1
132b16ca850c6c
1413994b4425cd
158d19000799d
hex4a768fccd79

5117067447673 has 2 divisors, whose sum is σ = 5117067447674. Its totient is φ = 5117067447672.

The previous prime is 5117067447617. The next prime is 5117067447697. The reversal of 5117067447673 is 3767447607115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4725875992464 + 391191455209 = 2173908^2 + 625453^2 .

It is a cyclic number.

It is not a de Polignac number, because 5117067447673 - 29 = 5117067447161 is a prime.

It is a super-2 number, since 2×51170674476732 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5117067427673) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2558533723836 + 2558533723837.

It is an arithmetic number, because the mean of its divisors is an integer number (2558533723837).

Almost surely, 25117067447673 is an apocalyptic number.

It is an amenable number.

5117067447673 is a deficient number, since it is larger than the sum of its proper divisors (1).

5117067447673 is an equidigital number, since it uses as much as digits as its factorization.

5117067447673 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20744640, while the sum is 58.

The spelling of 5117067447673 in words is "five trillion, one hundred seventeen billion, sixty-seven million, four hundred forty-seven thousand, six hundred seventy-three".