Base | Representation |
---|---|
bin | 100101001110110100011… |
… | …1111001100110110010001 |
3 | 200010012001020011122102101 |
4 | 1022131220333030312101 |
5 | 1132314223231311242 |
6 | 14514425350120401 |
7 | 1035460462435312 |
oct | 112355077146621 |
9 | 20105036148371 |
10 | 5117067447697 |
11 | 16a3155199737 |
12 | 6a787b650101 |
13 | 2b16ca850c8a |
14 | 13994b442609 |
15 | 8d1900079b7 |
hex | 4a768fccd91 |
5117067447697 has 2 divisors, whose sum is σ = 5117067447698. Its totient is φ = 5117067447696.
The previous prime is 5117067447673. The next prime is 5117067447727. The reversal of 5117067447697 is 7967447607115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3475655504721 + 1641411942976 = 1864311^2 + 1281176^2 .
It is a cyclic number.
It is not a de Polignac number, because 5117067447697 - 211 = 5117067445649 is a prime.
It is a super-3 number, since 3×51170674476973 (a number of 39 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (5117067447617) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2558533723848 + 2558533723849.
It is an arithmetic number, because the mean of its divisors is an integer number (2558533723849).
Almost surely, 25117067447697 is an apocalyptic number.
It is an amenable number.
5117067447697 is a deficient number, since it is larger than the sum of its proper divisors (1).
5117067447697 is an equidigital number, since it uses as much as digits as its factorization.
5117067447697 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62233920, while the sum is 64.
The spelling of 5117067447697 in words is "five trillion, one hundred seventeen billion, sixty-seven million, four hundred forty-seven thousand, six hundred ninety-seven".
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