Base | Representation |
---|---|
bin | 1001100010000110… |
… | …10010111100110101 |
3 | 111012200021000102221 |
4 | 10301003102330311 |
5 | 40440141234213 |
6 | 2203502402341 |
7 | 240553362535 |
oct | 46103227465 |
9 | 14180230387 |
10 | 5117914933 |
11 | 2196a2526a |
12 | ba9b903b1 |
13 | 637405741 |
14 | 3679d74c5 |
15 | 1ee49938d |
hex | 1310d2f35 |
5117914933 has 2 divisors, whose sum is σ = 5117914934. Its totient is φ = 5117914932.
The previous prime is 5117914909. The next prime is 5117914951. The reversal of 5117914933 is 3394197115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5089110244 + 28804689 = 71338^2 + 5367^2 .
It is a cyclic number.
It is not a de Polignac number, because 5117914933 - 221 = 5115817781 is a prime.
It is a super-2 number, since 2×51179149332 = 52386106522848788978, which contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5117914933.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5117914973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2558957466 + 2558957467.
It is an arithmetic number, because the mean of its divisors is an integer number (2558957467).
Almost surely, 25117914933 is an apocalyptic number.
It is an amenable number.
5117914933 is a deficient number, since it is larger than the sum of its proper divisors (1).
5117914933 is an equidigital number, since it uses as much as digits as its factorization.
5117914933 is an evil number, because the sum of its binary digits is even.
The product of its digits is 102060, while the sum is 43.
The square root of 5117914933 is about 71539.6039477435. The cubic root of 5117914933 is about 1723.3137545981.
The spelling of 5117914933 in words is "five billion, one hundred seventeen million, nine hundred fourteen thousand, nine hundred thirty-three".
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